# Line slope calculator 4x+7y=78

**Straight line given by points A[2; 10] and B[9; 6]**

## Calculation:

**Slope-intercept form of line:**y = -0.5714x+11.1429

**Canonical form of the line equation:**4x+7y-78 = 0

**Parametric form of the line equation:**

x = 7t+2

y = -4t+10 ; t ∈ R

**Slope:**m = -0.5714

**Slope angle of line: φ =**-29°44'42″ = -0.5191 rad

**X intercept:**x

_{0}= 19.5

**Y intercept:**y

_{0}= q = 11.1429

**Distance line from the origin:**d

_{0}= 9.6747

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(7; -4)

**Normal vector: n =**(4; 7)

**Midpoint of the segment AB: M =**[5.5; 8]

**Perpendicular Bisector equation:**7x-4y-6.5 = 0

**Vector OA = (2; 10) ; |OA| = 10.198**

**Vector OB = (9; 6) ; |OB| = 10.8167**

**Scalar product OA .OB = 78**

**Angle ∠ AOB = 45° = 0.7854 rad**