# Line slope calculator 8x+y=16

**Straight line given by points A[1; 8] and B[2; 0]**

## Calculation:

**Slope-intercept form of line:**y = -8x+16

**Canonical form of the line equation:**8x+y-16 = 0

**Parametric form of the line equation:**

x = t+1

y = -8t+8 ; t ∈ R

**Slope:**m = -8

**Slope angle of line: φ =**-82°52'30″ = -1.4464 rad

**X intercept:**x

_{0}= 2

**Y intercept:**y

_{0}= q = 16

**Distance line from the origin:**d

_{0}= 1.9846

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(1; -8)

**Normal vector: n =**(8; 1)

**Midpoint of the segment AB: M =**[1.5; 4]

**Perpendicular Bisector equation:**x-8y+30.5 = 0

**Vector OA = (1; 8) ; |OA| = 8.0623**

**Vector OB = (2; 0) ; |OB| = 2**

**Scalar product OA .OB = 2**

**Angle ∠ AOB = 82°52'30″ = 1.4464 rad**