# Line slope calculator x-5y=-18

**Straight line given by points A[2; 4] and B[7; 5]**

## Calculation:

**Slope-intercept form of line:**y = 0.2x+3.6

**Canonical form of the line equation:**x-5y+18 = 0

**Parametric form of the line equation:**

x = 5t+2

y = t+4 ; t ∈ R

**Slope:**m = 0.2

**Slope angle of line: φ =**11°18'36″ = 0.1974 rad

**X intercept:**x

_{0}= -18

**Y intercept:**y

_{0}= q = 3.6

**Distance line from the origin:**d

_{0}= 3.5301

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; 1)

**Normal vector: n =**(1; -5)

**Midpoint of the segment AB: M =**[4.5; 4.5]

**Perpendicular Bisector equation:**5x+y-27 = 0

**Vector OA = (2; 4) ; |OA| = 4.4721**

**Vector OB = (7; 5) ; |OB| = 8.6023**

**Scalar product OA .OB = 34**

**Angle ∠ AOB = 27°53'50″ = 0.4869 rad**